258. Add Digits

Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.

For example:

Given num = 38, the process is like: 3 + 8 = 111 + 1 = 2. Since 2 has only one digit, return it.

Follow up:
Could you do it without any loop/recursion in O(1) runtime?

class Solution {
    public int addDigits(int num) {
        while(num >= 10){
            num = num/10 + num%10;
        }
        return num;
    }
}

喜欢的话订阅一个呗~第一时间收到文章更新哟~

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